A gas absorbs a photon of 355 nm and emitted two wavelengths. If one of the emissions is at 680 nm, the other is at

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518 nm

1035 nm

325 nm

743 nm

answer is D.

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Detailed Solution

The conversion of energy required that $\frac{1}{355 n m} = \frac{1}{680 n m} + \frac{1}{λ} o r λ = \frac{(355 n m) (680 n m)}{(680 - 355) n m} = 743 n m$

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