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Q.

A gas absorbs photon of 355 nm and emits at two wavelengths, if one of the emission is at 680 nm, the other is at

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a

1035nm

b

325 nm

c

743 nm

d

518 nm

answer is C.

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Detailed Solution

Energy values are always additive,

$E_{t o t a l} = E_{1} + E_{2}$

$\frac{h c}{λ} = \frac{h c}{λ_{1}} + \frac{h c}{λ_{2}}$

$\frac{1}{355} = \frac{1}{680} + \frac{1}{λ_{2}}$

$λ_{2} = 742.94 n m \approx 743 n m$

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