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Q.

A gas at 27⁰C and pressure of 30 atm is allowed to expand to atmosphere pressure and volume 15 times larger. The final temperature of the gas is.....

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a

132⁰C

b

–123⁰C

c

123⁰C

d

–132⁰C

answer is A.

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Detailed Solution

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$T_{2} = \frac{P_{2} V_{2} T_{1}}{P_{1} V_{1}}$

$Here P_{1} = 30 atm, P 2 = 1 atm,$

$V_{1} = V and V_{2} = 15 V$

$T_{1} = 273 + 27 = 300 K$

$solving T_{2} = 150 K$

$t_{2} = 150 - 273 = - 123 K$

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