A gas cylinder contains 320gm of O2 at 30atm and 127∘C. What mass (in gram) of O2 would escape if first the cylinder is heated to 127∘C and then valve is held open until the pressure inside the cylinder becomes 1atm (the temperature being maintained at 127∘C)

It is known that;PV=WMRT ⇒P1W1T1=P2W2T230320×300=1W×400W=8gHence, 312 g is zone.

A gas cylinder contains 320gm of O2 at 30atm and 127∘C. What mass (in gram) of O2 would escape if first the cylinder is heated to 127∘C and then valve is held open until the pressure inside the cylinder becomes 1atm (the temperature being maintained at 127∘C)

It is known that;PV=WMRT ⇒P1W1T1=P2W2T230320×300=1W×400W=8gHence, 312 g is zone.

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A gas cylinder contains 320gm of $O_{2}$ at 30atm and $127^{\circ} C$ . What mass (in gram) of $O_{2}$ would escape if first the cylinder is heated to $127^{\circ} C$ and then valve is held open until the pressure inside the cylinder becomes 1atm (the temperature being maintained at $127^{\circ} C$ )

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Detailed Solution

It is known that;

$\begin{array}{l} P V = \frac{W}{M} R T \Rightarrow \frac{P_{1}}{W_{1} T_{1}} = \frac{P_{2}}{W_{2} T_{2}} \\ \frac{30}{320 \times 300} = \frac{1}{W \times 400} \\ W = 8 g \end{array}$

Hence, 312 g is zone.

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A gas cylinder contains 320gm of O2 at 30atm and 127∘C. What mass (in gram) of O2 would escape if first the cylinder is heated to 127∘C and then valve is held open until the pressure inside the cylinder becomes 1atm (the temperature being maintained at 127∘C)

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