A gas dissolved in water at 2 bar pressure. Its mole fraction is 0.02 in solution. The mole fraction of water when pressure of gas is doubled at same temperature is

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A gas dissolved in water at 2 bar pressure. Its mole fraction is 0.02 in solution. The mole fraction of water when pressure of gas is doubled at same temperature is

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0.98

0.92

0.94

0.96

answer is C.

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Detailed Solution

$P = K_{H} x$

$P \propto x$ sss

$\begin{array}{l} \frac{p_{1}}{p_{2}} = \frac{x_{1}}{x_{2}} \\ \frac{2}{4} = \frac{0.02}{x_{2}} \\ ∴ x_{2} = 0.04 \end{array}$

Mole fraction of water $= 1 - 0.04 = 0.96$

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