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Q.

A gas expands adiabatically at constant pressure such that its temperature T ∝ 1V, the value of CpCv of gas is

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a

1.50

b

1.67

c

2.00

d

1.30

answer is B.

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Detailed Solution

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TVγ-1 = constant ⇒ T ∝ V1-γ

According to question T ∝ V-12

Hence 1-γ = -12 ⇒ γ = 32= 1.5

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