A gas expands against a constant external pressure of 2.00 atm, increasing its volume by 3.40 L. Simultaneously, the system absorbs 400 J of heat from its surroundings. What is $∆ E,$ in joules, for this gas ?

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+289

-689

-289

+400

answer is B.

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Detailed Solution

Given, P = 2.00 atm,

$∆ V = 3.4 L q = 400 J Work done by gas w = - P ∆ V = - 2 \times 3.4 = - 6.8 L atm = - 6.8 \times 101.32 J = - 688.976 J ∆ E = q + (- w) = 400 + (- 688.976) = - 288.976 \approx - 289 J$

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