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Q.

A gas expands from 25 lit to 75 lit. at a constant pressure of 2 atm. (1 atm =105  Nm−2 ). Then work done by the gas during this expansion is 

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a

10 KJ

b

1 KJ

c

104 KJ

d

103 KJ

answer is C.

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Detailed Solution

Work done W=PdV=2×105×(75−25)×10−3=2×105×50×10−3=104J  
So, the correct answer is 3

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