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A gas in a cylinder is held at a constant pressure of $2.30 \times 10^{5} P a$ and is cooled and compressed from $1.70 m^{3}$ to $1.20 m^{3}$ . The internal energy of the gas decreases by $1.40 \times 10^{5} J$ . Find the absolute value $| Q |$ of the heat flow into or out of the gas and state the direction of the heat flow.

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$- 5.55 \times 10^{5} J,$ out of gas

$- 2.55 \times 10^{5} J,$ out of gas

$- 5.55 \times 10^{5} J,$ into the gas

$- 2.55 \times 10^{5} J,$ into the gas

answer is D.

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Detailed Solution

$Q = W + Δ U$

$= (- 1.15 \times 10^{5}) + (- 1.40 \times 10^{5})$

$= - 2.55 \times 10^{5} J$

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