A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy $∆ U$ of the gas in joules will be

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-500 J

-505 J

+505 J

1136.25 J

answer is B.

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Detailed Solution

As q = 0 so using I law of Thermodynamics.
$\begin{array}{l} ΔU = - p . ΔV \\ = - 2 .5 (4 .5 - 2 .5) = - 5 lit atm \\ = - 5 \times 101 .3 = - 506 .5 J oule \\ = - 505 J \end{array}$

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