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A gas is compressed at a constant pressure of 100 $\frac{N}{m^{2}}$ from a volume $20 m^{3}$ to a volume of 14 $m^{3}$ . 100J of heat is added to the gas then its internal energy

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Increases by 700J

Increases by 500J

Decreases by 400J

Decreases by 200J

answer is B.

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Detailed Solution

$\begin{array}{l} d w = P (V_{2} - V_{1}) \\ d w = 100 (14 - 20) \\ = - 600 \\ Δ U = Δ Q - Δ w \\ = 100 - (- 600) \\ = 700 J \end{array}$

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