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Q.

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A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature (V0, T0). From the details given in the graph, find the value of adiabatic constant γ

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a

V0T0tan θ+1

b

V0 tan θT0+1

c

V0 tan2θT0+1

d

V0T0+tan θ

answer is A.

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Detailed Solution

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We have, for an adiabatic process, in relation with temperature and volume
TVγ-1 = constant
Differentiating with respect to T.
Vγ-1.1 + T.(γ-1)Vγ-2dVdT = 0

dVdT = VT(γ-1)

But from the graph dVdT(T0,V0)= tan(π-θ) = -tan θ

V0T0(γ-1) = tan θ  γ-1 = V0T0tan θ

γ = V0T0tan θ+1

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