Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A gas (Molar mass = 280g/Mol) was burnt in excess O2 in a constant volume calorimeter and during combustion the temperature of the calorimeter is increased from 298 K to 298.45 K. If the heat capacity of a calorimeter is 2.5 kJ K1 and the enthalpy of combustion of gas is 9 kJ mol1 then the amount of gas burnt is ______g. 

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

35

b

65

c

55

d

45

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

ΔH=ΔU+0 (W=0 at constant volume)

X/280 moles give 2.5 x 0.45KJ
 1 mole give =2.5 x 0.45 x 280 / X = 9
X = 35 g

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
A gas (Molar mass = 280g/Mol) was burnt in excess O2 in a constant volume calorimeter and during combustion the temperature of the calorimeter is increased from 298 K to 298.45 K. If the heat capacity of a calorimeter is 2.5 kJ K−1 and the enthalpy of combustion of gas is 9 kJ mol−1 then the amount of gas burnt is ______g.