A gas obeys PV² = constant in addition to PV = RT. If on heating, the temperature is doubled, the volume of the gas is

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V/2

$V / \sqrt{2}$

$\sqrt{2} V$

answer is A.

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Detailed Solution

$\begin{array}{l} {PV}^{2} = const; \frac{RT}{V} \times V^{2} = const \\ TV = const \\ V α \frac{1}{T} \Rightarrow \frac{V_{1}}{V_{2}} = \frac{T_{2}}{T_{1}} \Rightarrow \frac{V}{V_{2}} = \frac{2 T}{T} \Rightarrow V_{2} = \frac{V}{2} \end{array}$

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