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A gas of volume 2000ml is kept in a vessel at a pressure of $10^{3}$ pascals at a temperature of $27^{0} C$ . If the pressure is increased to $10^{5}$ pascals at the same temperature, the volume of the gas becomes

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$200 m l$

$20 m l$

$1000 m l$

$2 m l$

answer is B.

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Detailed Solution

$P_{1} V_{1} = P_{2} V_{2}$

$10^{3} (2000) = 10^{5} (V_{2}) V_{2} = 20 m l$

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