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Q.

A gas undergoes an adiabatic process and an isothermal process. The two processes are plotted on a p-V diagram. The resulting curves intersect at a point P. Tangents are drawn to the two curves at P. These make angles of 135oand 121o with the positive V-axis. The gas is likely to be [Given tan590 =1.67] [p = pressure, V=volume of gas]

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a

Diatomic

b

Triatomic

c

Monatomic

d

A mixture of monatomic and diatomic gases

answer is A.

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Detailed Solution

Slope of isothermal curve =pv=tan 135° 
Slope of Adiabatic curve= γPV=tan 121°=tan 59° 
 

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