A gas undergoes change in its state from position A to position B via three different paths as shown in figure. Select the correct alternatives.

Internal energy (U) depends only on the initial and final states. Hence  $\Delta U$  will be same in al the three paths. In all the three paths, work done by the gas is positive and the product  $PV$  or temperature T is increasing. Therefore, internal energy is also increasing. So from the first law of thermodynamics heat will be absorbed by the gas
Further, area under P-V graph is maximum in path I while  $\Delta U$  is same for all the three paths. Therefore, heat absorbed by the gas is maximum in path I.
For temperature of the gas, we can see that product PV first increases in path, but whether it is decreasing or increasing later on we cannot say anything about it unless the exact values are known to us