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A gaseous alkane requires five times its volume of oxygen under the same conditions for complete combustion. The molecular formula of the alkane is

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CH₄

C₂H₆

C₄H₁₀

C₄H₈

answer is C.

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Detailed Solution

$C_{2} H_{6} + \frac{7}{2} O_{2} \to 2 {CO}_{2} + 3 H_{2} O C_{6} H_{14} + \frac{19}{2} O_{2} \to 6 {CO}_{2} + 7 H_{2} O C_{3} H_{8} + 5 O_{2} \to 3 {CO}_{2} + 4 H_{2} O {CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O$

1 volume of C₃H₈ requires 5 volumes of O₂ for complete combustion

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