Q.

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio of Cp and Cv is

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a

1.4

b

1.54

c

1.59

d

1.62

answer is D.

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Detailed Solution

For m1=16gm;2He4M1=4
n1=m1M1=164=4moles;CV1=32R;CP1=52R For 8O16,m2=16gm;M2=32gm,CV2=52R;CP2=72R;n2=m2M2=1632=0.5moleCVmix =n1CV1+n2CV2n1+n2=4×32R+0.5×52R4+0.5CVmix =14.54.5×2
Cpmix =n1Cp1+n2Cp2n1+n2=23.59Rγ=Cpmix CV mix =23.54R14.59R=1.62

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