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A gaseous mixture containing 0.35g of $N_{2} and 5600 ml of O_{2}$ at STP is kept in a 5 litres flask at 300K. The total pressure of the gaseous mixture is

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12.315atm

0.616atm

1.293atm

1.2315atm

answer is A.

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Detailed Solution

P = $\frac{(n_{1} + n_{2}) RT}{V}$

$= \frac{(\frac{0.35}{28} + \frac{5600}{22400}) (0.0821) (300)}{5}$

$= (0.0125 + 0.25) (0.0821) (60)$

$= (0.2625) (0.0821) (60)$

= 1.293

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