A gaseous mixture contains $40 % O_{2}, 40 % N_{2}, 10 % C O_{2}, 10 % C H_{4}$ by volume. Calculate the vapour density of the gaseous mixture.

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answer is 15.

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Detailed Solution

$M_{w} = \frac{40 \times 32 + 40 \times 28 + 10 \times 44 + 10 \times 16}{100} = \frac{1280 + 1120 + 440 + 160}{100} = \frac{3000}{100} = 30$
Vapor density $\frac{M_{w}}{2} = \frac{30}{2} = 15$

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