A gaseous mixture contains oxygen and nitrogen in the ratio $1 : 4$ by weight. The ratio of their number of molecules is

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$3 : 16$

$4 : 1$

$7 : 32$

$1 : 4$

answer is C.

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Detailed Solution

Let's consider the ratio $1 : 4$ as, $1 g$ of oxygen and $4 g$ of nitrogen individually.

As we know,

No. of molecules $= ($ Given weight/molecular weight $) \times N_{A}$

No. of molecules of $O = 1 / 32 \times N_{A}$

No. of molecules of $N = 4 / 28 \times N_{A} = 1 / 7 N_{A}$

Hence, ratio $=$ no. of molecules of $O /$ no. of molecules of $N$

$= (1 / 32 N_{A}) / (1 / 7 N_{A}) = 7 : 32$

Therefore, option (C) is correct.

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