A gaseous mixture contains SO3(g) and C2H6(g) in a 16:15 ratio by mass. The ratio of total number of atoms present in C2H6(g) and SO3(g) is :

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A gaseous mixture contains $S O_{3} (g)$ and $C_{2} H_{6} (g)$ in a 16:15 ratio by mass. The ratio of total number of atoms present in $C_{2} H_{6} (g)$ and $S O_{3} (g)$ is :

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1: 5

2: 5

5: 1

5: 2

answer is C.

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Detailed Solution

The ratios of the molecules,

$\begin{array}{l} {SO}_{2} : C_{2} H_{6} \\ \frac{16}{80} \times 4 : \frac{15}{30} \times 8 \end{array}$

$= \frac{4}{5} : 4 = 1 : 5; Ans = 5 : 1$

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