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A gaseous mixture of propane and butane of volume 3 litre on complete combustion produces 11.0 litre $C O_{2}$ under standard conditions of temperature and pressure
The ratio of volume of butane to propane is :

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3 : 1

3 : 2

2 : 1

1 : 2

answer is B.

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Detailed Solution

$\begin{array}{l} C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O \\ V 5 V 3 V \end{array}$

$\begin{array}{l} C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O \\ 3 - v \frac{13}{2} (3 - v) 4 (3 - v) \end{array}$

$3 V + 4 (3 - v) = 11$

$V = 1$

$V_{C_{4} H_{10}} = 3 - 1 = 2 L$

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