A Gaussian surface in the figure is shown by dotted line The electric field on the surface will be

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Due to all

Due to q₁ and q₂ only

Due to q₂ only

Zero

answer is D.

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Detailed Solution

The flux through the Gaussian surface is due to the charge inside the Gaussian surface.
But the electric field on the Gaussian surface is the vector sum of electric fields due to
all the charges i.e., $q_{1} - q_{1} and q_{2}$

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