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A Geigger Muller counter is used to study the radioactive process. In the absence of radioactive substance A, it counts 3 disintegration per second (dps).At the start in the presence of A, it records 23 dpr; and after 10 min 13 dps,
i. What does it count after 20 min?
ii. What is the half life of A?

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8 dps, 10 min

5 dps, 10 min

5 dps, 20 min

5 dps, 5 min

answer is A.

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Detailed Solution

In the absence of A, 3 dps is zero error, hence
Initial count = 23 - 3 = 20 dps
After 10 min = 13 - 3 = 10 dps
After 20 min = 5 dps (recorded = 5 + 3 = 8 dps)
(50% fall in 10 min, T₅₀=10 min)

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