A geostationary satellite is at a height h above the surface of earth. If earth radius is R , then

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The area on earth escaped from this satellite is given as $2 π R^{2} (1 + \cos θ)$

The maximum co-altitude on earth upto which the satellite can be used for communication is
$\sin^{- 1} (R / R + h)$

The area on earth escaped from this satellite is given as $2 π R^{2} (1 + \sin θ)$

The minimum co-altitude on earth upto which the satellite can be used for communication is
$\sin^{- 1} (R / R + h)$

answer is A, C.

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Detailed Solution

From diagram $\sin θ = R / R + h$

minimum co-altitude $= \sin^{- 1} (R / R + h)$

The curved area AB on earth $= 2 π R^{2} (1 - \sin θ)$

Area on earth escaped from satellite

$= 4 π R^{2} - 2 π R^{2} (1 - \sin θ)$

$= 2 π R^{2} (1 + \sin θ)$

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