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Q.

A geostationary satellite is orbiting around an arbitrary planet ‘P’ at a height of 11 R above the surface of ‘P’, R being the radius of ‘P’ .The time period of another satellite in hours at a height of 2R from the surface of 'P' is...….('P' has the time period of 24 hours).

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a

62

b

62

c

3

d

5

answer is A.

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Detailed Solution

T2∝R3 ⇒T1T2=R1R23/2 ⇒24T2=11+12+132=8  ⇒T2=3 hr

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