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Q.

A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth. The
time period of another satellite at a height of 2.5R from the surface of the earth is

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a

8hr 

b

 62 hr

c

 6hr

d

12hr

answer is D.

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Detailed Solution

T=2π(R+h)3GM⇒T1T2=(R+h1R+h2)3/2

⇒24T2=[R+6RR+2.5R]3/2  ∴T2=62hr

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