A girl standing on road holds her umbrella at 45° with the vertical to keep the rain away. If she starts running without umbrella with a speed of 152kmh-1, the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is :

V=tanθ=VGVRG⇒1=VGVRG⇒152=VRG

A girl standing on road holds her umbrella at 45° with the vertical to keep the rain away. If she starts running without umbrella with a speed of 152kmh-1, the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is :

V=tanθ=VGVRG⇒1=VGVRG⇒152=VRG

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A girl standing on road holds her umbrella at $45 °$ with the vertical to keep the rain away. If she starts running without umbrella with a speed of $15 \sqrt{2} {kmh}^{- 1}$ , the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is :

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$\frac{30}{\sqrt{2}} k m h^{- 1}$

$25 k m h^{- 1}$

$30 {kmh}^{- 1}$

$\frac{25}{\sqrt{2}} k m h^{- 1}$

answer is C.

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$V = \tan θ = \frac{V_{G}}{V_{R G}}$

$\Rightarrow 1 = \frac{V_{G}}{V_{R G}} \Rightarrow 15 \sqrt{2} = V_{R G}$

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A girl standing on road holds her umbrella at 45° with the vertical to keep the rain away. If she starts running without umbrella with a speed of 152kmh-1, the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is :

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A girl standing on road holds her umbrella at $45 °$ with the vertical to keep the rain away. If she starts running without umbrella with a speed of $15 \sqrt{2} {kmh}^{- 1}$ , the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is :