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A girl stands on a box $60 cm$ in length, $40 cm$ in breadth, and $20 cm$ in width in three ways. In which of the following cases the pressure exerted by the brick will be

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Maximum when length and breadth form the base

Maximum when breadth and width form the base

Maximum when width and length form the base

Same in all the above three cases

answer is B.

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Detailed Solution

In the above case, the pressure exerted by the brick will be maximum when breadth and width form the base.
When length and breadth form the base, the area of contact

= length \times breadth

= 60 \times 40

= 2400 {cm}^{2}

When breadth and width form the base, area of contact

= breadth \times width

= 40 \times 20

= 800 {cm}^{2}

When width and length form the base, area of contact

= width \times length

= 20 \times 60

= 1200 {cm}^{2}

We know that pressure exerted by a force is inversely proportional to the area it is applied upon by the following formula,

P = \frac{F}{A}

, Where,

P

is the Pressure,

F

is the Force applied and,

A

is the area.
Pressure is maximum when the area is minimum. Hence, pressure is maximum when breadth and width form the base.

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