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A girl stands on a box having $10 cm$ length, $40 cm$ breadth and $20 cm$ width in three ways in which of the following cases, the pressure exerted by the brick will be:

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maximum when length and breadth form the base

maximum when length and width form the base

maximum when width and length form the base

same in all the above three cases

answer is B.

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Detailed Solution

A girl stands on a box having

10 cm

length,

40 cm

breadth and

20 cm

width in three ways in. The pressure exerted by the brick will be maximum when length and width form the base.
We know,

Pressure = \frac{Force}{Area}

So, pressure will be maximum when the area will be minimum.
Here length

= 60 cm

, breadth

= 40 cm

and width

= 20 cm

Area of the base formed by length and breadth

= 60 \times 40

= 2400 {cm}^{2}

Area of the base formed by breadth and width

= 40 \times 20

= 800 {cm}^{2}

Area of the base formed by width and length

= 20 \times 60

= 1200 {cm}^{2}

Here, the area of the base formed by breadth and width is minimum so, pressure will be maximum.

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