Q.

a. Give reasons for the following:
(i) Sulphur in vapor state shows paramagnetic behavior.
(ii) N-N bond is weaker than P-P bond.
(iii) Ozone is thermodynamically less stable than oxygen.

b. Write the name of gas released when Cu is added to
(i) dilute HNO3 and
(ii) conc. HNO3

OR

(a) (i) Write the disproportionation reaction of H3PO3.
      (ii) Draw the structure of XeF4.
(b) Account for the following:
(i) Although Fluorine has less negative electron gain enthalpy yet F2 is strong oxidizing agent.
(ii) Acidic character decreases from N2O3 to Bi2O3 in group 15.
(c) Write a chemical reaction to test sulphur dioxide gas. Write chemical equation involved.

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Detailed Solution

a. (i) Sulphur partly exist as S2  in vapour state. It has 2 unpaired electrons which make it paramagnetic.
    (ii) N has small size as compared to P. Due to which N-N bond inter-electronic repulsion is more. Therefore, N-N bond weaker than P-P bond.
   (iii) The decomposition of ozone leads to formation of oxygen. In this process large amount of heat is liberated with increase in entropy. It results into large negative Gibbs free energy change. Therefore, ozone is thermodynamically less stable.

b. (i) Nitric oxide
    (ii) Nitrogen dioxide

OR

(a) (i) H3PO33H3PO4+PH3
(ii) Question Image
(b) (i) Fluorine has small size low bond dissociation enthalpy which makes it a strong oxidizing agent.
(ii) On going down the group the size of elements increases. It decreases the electronegativity. Due to which acidic character decreases.
(c) 5SO2+2MnO4+2H2O5SO42+4H++2Mn2+

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