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Q.

A given initial mass of KClO₃on 50 % decomposition produces 67.2 litre oxygen gas at $0^{\circ} C$ and 1 atm . The other product of decomposition is KCl. The initial mass of KClO₃ (in gm) taken is :

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a

245

b

122.5

c

none of these

d

490

answer is C.

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Detailed Solution

${KClO}_{3} ⟶ KCl + \frac{3}{2} O_{2}$

Mass decomposed $= \frac{50 m}{100} \frac{3}{2} \times \frac{50 m}{100 \times 122.5}$

Moles $\frac{50 m}{100 \times 122.5} = \frac{67.2}{22.4}$

$m = 490 gm$

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