A glass capillary tube inner diameter 0.28mm is lowered vertically into water in a vessel. The pressure to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel in Nm^-2 is (surface tension of water = 0.07Nm^-1Atmospheric pressure = 10⁵Nm^-2)______________ $\times 10^{3}$ .

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answer is 101.

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Detailed Solution

The meniscus in capillary creates a negative gauge pressure

$p = - \frac{2 T}{r}$

To neutralize it we have to apply a positive gauge pressure

$p = \frac{2 T}{R} = \frac{2 \times 7 \times 10^{- 2}}{0.14 \times 10^{- 3}}$

$p = 10^{3}$

$p_{abs} = p_{g} + p_{atm} = 10^{3} + 10^{5} = 101 \times 10^{3}$

Hence the correct answer is 101.

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