A glass convex lens $(μ_{g} = 1 .5)$ has a focal length of 8 cm when placed in air. What would be the focal length of the lens when it is immersed in water ( $μ_{w} = 1 .33$ ) ?

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2 m

4 cm

16 cm

32 cm

answer is D.

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Detailed Solution

$\frac{f_{l}}{f_{a}} = \frac{(_{a} μ_{g} - 1)}{(_{a} μ_{g} - 1)} \Rightarrow \frac{f_{w}}{f_{a}} = \frac{(1 .5 - 1)}{(\frac{1 .5}{133} - 1)} \Rightarrow f_{w} = 32 cm$

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