A glass plate of length 10cm, breadth 1.54cm and thickness 0.20cm weighs 8.2g in air. It is held vertically with the long side horizontal and the lower half under water. The apparent weight of the plate, is found to be (W+0.1796)gm.wt. Find W.
Surface tension of water = 7.3 x10^-2 N / m and g = 9.8m/ s² )

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Detailed Solution

$TL = 7.3 \times 10^{- 2} \times [2 (10 + 0 .2) \times 10^{- 2}] = 14 .892 \times 10^{- 3} N$
Apparent weight of plate = wt. of. plate in air + surface tension force – upthrust
$= 8 .2 \times 10^{- 3} + \frac{14 .892 \times 10^{- 3}}{9 .8} - \frac{1.54 \times 10^{- 6} \times 10^{3} \times 9 .8}{9 .8} = (8.2 + 1.51959 - 1.54) \times 10^{- 3} = 8 .1796 \times 10^{- 3} kg wt = 8 .1796 g wt$

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