A glass rod of radius 1.0mm is inserted symmetrically into a vertical capillary tube of radius 2.0 mm such that their lower ends are at the same level. The arrangement is now dipped in water. The height to which the water rises in the capilary tube is (T = 75×10^-3 N/m)

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15mm

5 mm

10 mm

20 mm

answer is C.

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Detailed Solution

$\begin{array}{l} T = 75 \times 10^{- 3} N / m \\ h = \frac{2 Tcos θ}{ρgr} = \frac{2 \times 75 \times 10^{- 3}}{10^{3} \times 10 \times 10^{- 3}} \\ = \frac{150}{10} \times 10^{- 3} m = 15 mm \end{array}$
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