AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A glass sphere of diameter 50 cm and $μ = 1.5$ has a small air bubble. Looking from outside the diameter, the bubble appears to be at a distance 10 cm from the surface. Find the apparent position of the bubble when it is viewed from the diametrically opposite position.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

real image, at the pole of 1st face

virtual image, at the centre of the sphere

virtual image, at the pole of 1st face

real image, at the pole of 2nd face

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

For refraction at first surface :

u = - x , V = 10 cm,

$\frac{μ_{2}}{V} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$

$\Rightarrow \frac{1}{- 10} - \frac{1 .5}{(- x)} = \frac{1 - 1 .5}{- 25}$

$\Rightarrow \frac{3}{2 x} = \frac{1}{50} + \frac{1}{10} \Rightarrow x = 12.5 cm$

For refraction at second surface :

$u = - (50 - 12 .5) = - 37 .5 cm$

$\frac{μ_{2}}{V} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$

$\Rightarrow \frac{1}{V} - \frac{1 .5}{- 37 .5} = \frac{1 - 1 .5}{- 25}$

$\Rightarrow \frac{1}{V} = \frac{1}{50} - \frac{1 .5}{37 .5} \Rightarrow V = - 50 cm$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!