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Q.

A glass sphere of radius 10 cm has refractive index μ=1.5. A is the position of a point object and B is its image. If A and B are equidistant from the surface of the sphere then separation between A and B is

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a

40 cm

b

60 cm

c

50 cm

d

70 cm

answer is B.

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Detailed Solution

Since AP = BQ, the refracted ray MN inside the sphere, must be parallel to the diameter PQ. 

For first refraction at the surface of the sphere

1α−1−AP=1.5−1+10⇒AP=20 cm

∴Distance AB=AP+PQ+QB=20+20+20cm=60 cm

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