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A glass tube 1 m length is completely filled with water. The water can be drained out slowly at the bottom of the tube. If a vibrating fork of frequency 500 Hz is brought at the upper end of the tube, then what is the total number of resonances obtained ? (velocity of sound is 300 $m s^{- 1}$ )

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answer is C.

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Detailed Solution

f= $(2 n - 1) \frac{v}{4 l}$
first resonance l= $\frac{v}{4 f} = \frac{300}{4 \times 500} \times 100 15 c m n e x t 45 c m, 75 c m a n d s o o n b u t i t c a n n o t b e m o r e t h a n 100 s o 3 r e s o n a n c e w i l l b e h e a r d$

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