A glass tube of diameter 0.06 cm is dipped in methyl alcohol, if angle of contact is 0°, density of methyl alcohol 0.8g cm^–3 and surface tension 0.023 Nm^–1 the height to which it rises in the tube is

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2 mm

1 cm

2 cm

4 cm

answer is B.

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Detailed Solution

$\begin{array}{l} h = \frac{2 Tcos θ}{ρgr} = \frac{2 \times 0 .023}{0 .8 \times 10^{3} \times 9 .8 \times 0 .03 \times 10^{- 2}} \\ = 0 .019 m = 2 cm \end{array}$

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