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A G.M. counter is used to study the radioactive process of first-order. In absence of radioactive substance A, it-counts 3 disintegration per second (dps). When A is placed in the G.M. counter, it records 23 dps at the start and 13 dps after 10 minutes. It records x dps after next 10 minutes and A has half-life period y minutes. x and y are :

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5 dps, 5 min

8 dps, 10 min

5 dps, 20 min

5 dps, 10 min

answer is A.

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Detailed Solution

$[A]_{0} \propto 23 - 3$

$[A]_{t} \propto 13 - 3$

So,

$\Rightarrow t_{1 / 2} = 10 \min$

At t= 20 min,

$[A]_{t} \propto 5$

G.M. counter $\to 5 + 3 = 8$

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