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A golf ball is lowered into a measuring cylinder containing water, the volume of water replaced by the ball is $30 {cm}^{3}$ , when the ball is completely submerged. If the mass of ball in air is $60 g$ , then its density is__

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1.1 g / {cm}^{3}

2.0 g / {cm}^{3}

3.0 g / {cm}^{3}

4.0 g / {cm}^{3}

answer is B.

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Detailed Solution

The density of the ball is

2.0 g / {cm}^{3}

Given data:
volume of water replaced, when the ball is submerged

= 30 {cm}^{3}

volume of water displaced

=

volume of ball immersed fully
Hence the volume of the ball,

V = 30 {cm}^{3}

Mass of the ball,

m = 60 g

To find the density of the ball.
Formula used:

Density (d) = \frac{Mass (m)}{Volume (V)}

\Rightarrow

= \frac{33}{30}

\Rightarrow

= 1.1 g / {cm}^{3}

Hence the density of the ball is

1.1 g / {cm}^{3}

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