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A graph is plotted for an element by putting its mass on X-axis and the corresponding number of atoms on Y-axis. What is the atomic mass of the element for which the graph is plotted? $(N_{A} = 6.0 \times 10^{23})$

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answer is B.

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Detailed Solution

$S l o p e = \frac{N_{A}}{A t o m i c m a s s} = 1.5 \times 10^{22} \Rightarrow A t o m i c m a s s = 40$

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