A graph of $x$ versus $t$ is shown in figure. Choose the correct alternatives given below

1)As per the diagram, at point $A$ the graph is parallel to time axis hence, $v=\frac{dx}{dt}=0$. As the starting point is $A$ hence, we can say that the particle is starting from rest. 

2)At B slope is zero , so velocity is zero and beyond point B slope is negative , so velocity is negative. Therefore at B a$<0.$

3) Between A and D direction of displacement vector is along negative x axis . Hence average velocity is negative .

4)From the graph it is clear that

                        $\left|\mathrm{slope} \mathrm{at} \mathrm{D}\right|>\left|\mathrm{slope} \mathrm{at} \mathrm{E}\right|$

Hence, speed at $D$ will be more than at $E$.