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A guard of 12 men is formed from a group of ‘n’ soldiers. It is found that 2 particular soldiers A and B are 3 times as often together on guard as 3 particulars soldiers C, D and E. Then $(n - 24)$ is equal to

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answer is A.

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Detailed Solution

$^{n - 2} C_{12 - 2} = 3 .^{n - 3} C_{12 - 3}$

$^{n - 2} C_{10} = 3 .^{n - 3} C_{9}$

$\frac{n - 2}{10} = 3 \Rightarrow n = 32$

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