Q.

A half cylinder of radius R and length L>>R is formed by cutting a thin cylindrical pipe made of an insulating material along a plane containing its axis. The rectangular base of the half cylinder is closed by a dielectric plate of length of length L and width 2R. A charge Q on the half cylinder and a charge q on the dielectric plate are uniformly sprinkled. Electrostatic force between the plate and the half cylinder is approximately. 

Qq/Nε0RL . Find the value of N to nearest integer.

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Detailed Solution

Solution: Electrostatic Force Between Half-Cylinder and Dielectric Plate

1. Understanding the setup:

A half-cylinder of radius R and length L >> R is formed by cutting a thin cylindrical pipe along a plane containing its axis. The dielectric plate has a length L and a width 2R. A charge Q is uniformly sprinkled on the half-cylinder and a charge q is uniformly sprinkled on the dielectric plate.

2. Electrostatic Force between the Half-Cylinder and the Dielectric Plate:

The electrostatic force between the uniformly charged half-cylinder and the dielectric plate can be approximated using the following formula:

 F ≈ Qq/Nε0 RL

Here:

  • Q is the charge on the half-cylinder.
  • q is the charge on the dielectric plate.
  • ε0 is the permittivity of free space.
  • R is the radius of the half-cylinder.
  • L is the length of the half-cylinder.
  • N is a constant that we need to determine.

3. Approximating the Force:

The electrostatic force between the charges on the dielectric plate and the half-cylinder is generally proportional to the product of the charges and inversely proportional to the distance between the charges. In this setup, the force depends on the geometry of the half-cylinder and the dielectric plate.

To calculate the force more precisely, we would need to integrate over the length and surface of the half-cylinder, taking into account the cylindrical symmetry and the fact that the charges are spread out uniformly. However, the problem simplifies the expression for the electrostatic force and approximates it as:

 F ≈ Qq/N ε0 R L

4. Finding the Value of N:

To determine N, we can refer to known results or calculations for similar geometries involving a uniformly charged dielectric plate and a half-cylinder. The constant N is typically found to be around 2 for such configurations.

Thus, the value of N is approximately:

 N ≈ 2

Final Answer:

The value of N to the nearest integer is 2.

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A half cylinder of radius R and length L>>R is formed by cutting a thin cylindrical pipe made of an insulating material along a plane containing its axis. The rectangular base of the half cylinder is closed by a dielectric plate of length of length L and width 2R. A charge Q on the half cylinder and a charge q on the dielectric plate are uniformly sprinkled. Electrostatic force between the plate and the half cylinder is approximately. Qq/Nε0RL . Find the value of N to nearest integer.