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Q.

A hammer of mass I kg having speed of 50 m,/s, hit a iron nail of mass 200 gm. If specific heat of iron is 0.105 cal/gm°C and half the energy is converted into heat, the rise in temperature of nail is

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a

7.1°C

b

9.2°C

c

10.5°C

d

12.1°C

answer is A.

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Detailed Solution

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W = JQ  12(12Mv2) = J(m.c.θ)

 14×1×(50)2 = 4.2[200×0.105×θ]

 θ = 7.1°C

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