A hanging mass $M$ is connected to a four times bigger mass by using a string-pulley arrangement as shown in the figure. The bigger mass is placed on a horizontal ice-slab and being pulled by 2mg force. In this situation tension in the string is $\frac{x}{5} M g$ for $x =$ (Neglect mass of the string and friction of the block (bigger mass) with ice slab.)(given $g =$ acceleration due to gravity)

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answer is 6.

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Detailed Solution

For the 4M Kg block :

$2 Mg - T = 4 Ma$

For the M kg block :

$T - Mg = Ma$

Solving the above equations for T :

$T = \frac{6 Mg}{5}$

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